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1/2x+4=x-11
We move all terms to the left:
1/2x+4-(x-11)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-x+11+4=0
We multiply all the terms by the denominator
-x*2x+11*2x+4*2x+1=0
Wy multiply elements
-2x^2+22x+8x+1=0
We add all the numbers together, and all the variables
-2x^2+30x+1=0
a = -2; b = 30; c = +1;
Δ = b2-4ac
Δ = 302-4·(-2)·1
Δ = 908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{908}=\sqrt{4*227}=\sqrt{4}*\sqrt{227}=2\sqrt{227}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{227}}{2*-2}=\frac{-30-2\sqrt{227}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{227}}{2*-2}=\frac{-30+2\sqrt{227}}{-4} $
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