1/2x+4=2x-0.5

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Solution for 1/2x+4=2x-0.5 equation:



1/2x+4=2x-0.5
We move all terms to the left:
1/2x+4-(2x-0.5)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We get rid of parentheses
1/2x-2x+0.5+4=0
We multiply all the terms by the denominator
-2x*2x+(0.5)*2x+4*2x+1=0
We multiply parentheses
-2x*2x+x+4*2x+1=0
Wy multiply elements
-4x^2+x+8x+1=0
We add all the numbers together, and all the variables
-4x^2+9x+1=0
a = -4; b = 9; c = +1;
Δ = b2-4ac
Δ = 92-4·(-4)·1
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{97}}{2*-4}=\frac{-9-\sqrt{97}}{-8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{97}}{2*-4}=\frac{-9+\sqrt{97}}{-8} $

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