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1/2x+3=4.5x
We move all terms to the left:
1/2x+3-(4.5x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(+4.5x)+3=0
We get rid of parentheses
1/2x-4.5x+3=0
We multiply all the terms by the denominator
-(4.5x)*2x+3*2x+1=0
We add all the numbers together, and all the variables
-(+4.5x)*2x+3*2x+1=0
We multiply parentheses
-8x^2+3*2x+1=0
Wy multiply elements
-8x^2+6x+1=0
a = -8; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·(-8)·1
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{17}}{2*-8}=\frac{-6-2\sqrt{17}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{17}}{2*-8}=\frac{-6+2\sqrt{17}}{-16} $
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