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1/2x+3=2(x-2/5)
We move all terms to the left:
1/2x+3-(2(x-2/5))=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(2(+x-2/5))+3=0
We calculate fractions
()/10x^2+(-(2(+x-2*2x)/10x^2+3=0
We calculate fractions
We do not support expression: x^4
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