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1/2x+30=12+x
We move all terms to the left:
1/2x+30-(12+x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(x+12)+30=0
We get rid of parentheses
1/2x-x-12+30=0
We multiply all the terms by the denominator
-x*2x-12*2x+30*2x+1=0
Wy multiply elements
-2x^2-24x+60x+1=0
We add all the numbers together, and all the variables
-2x^2+36x+1=0
a = -2; b = 36; c = +1;
Δ = b2-4ac
Δ = 362-4·(-2)·1
Δ = 1304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1304}=\sqrt{4*326}=\sqrt{4}*\sqrt{326}=2\sqrt{326}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2\sqrt{326}}{2*-2}=\frac{-36-2\sqrt{326}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2\sqrt{326}}{2*-2}=\frac{-36+2\sqrt{326}}{-4} $
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