1/2x+3/4x=20

Solution for 1/2x+3/4x=20 equation:

1/2x+3/4x=20

We move all terms to the left:

1/2x+3/4x-(20)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We calculate fractions


4x/8x^2+6x/8x^2-20=0

We multiply all the terms by the denominator


4x+6x-20*8x^2=0

We add all the numbers together, and all the variables

10x-20*8x^2=0

Wy multiply elements

-160x^2+10x=0

a = -160; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-160)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-160}=\frac{-20}{-320}
=1/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-160}=\frac{0}{-320}
=0
$