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1/2x+3/4=5/8x-2
We move all terms to the left:
1/2x+3/4-(5/8x-2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 8x-2)!=0We get rid of parentheses
x∈R
1/2x-5/8x+2+3/4=0
We calculate fractions
384x^2/256x^2+128x/256x^2+(-160x)/256x^2+2=0
We multiply all the terms by the denominator
384x^2+128x+(-160x)+2*256x^2=0
Wy multiply elements
384x^2+512x^2+128x+(-160x)=0
We get rid of parentheses
384x^2+512x^2+128x-160x=0
We add all the numbers together, and all the variables
896x^2-32x=0
a = 896; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·896·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*896}=\frac{0}{1792} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*896}=\frac{64}{1792} =1/28 $
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