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1/2x+3(1/3x+5)=45
We move all terms to the left:
1/2x+3(1/3x+5)-(45)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x+5)!=0We multiply parentheses
x∈R
1/2x+3x+15-45=0
We multiply all the terms by the denominator
3x*2x+15*2x-45*2x+1=0
Wy multiply elements
6x^2+30x-90x+1=0
We add all the numbers together, and all the variables
6x^2-60x+1=0
a = 6; b = -60; c = +1;
Δ = b2-4ac
Δ = -602-4·6·1
Δ = 3576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3576}=\sqrt{4*894}=\sqrt{4}*\sqrt{894}=2\sqrt{894}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-2\sqrt{894}}{2*6}=\frac{60-2\sqrt{894}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+2\sqrt{894}}{2*6}=\frac{60+2\sqrt{894}}{12} $
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