1/2x+2=16x-1

Solution for 1/2x+2=16x-1 equation:

1/2x+2=16x-1

We move all terms to the left:

1/2x+2-(16x-1)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

1/2x-16x+1+2=0

We multiply all the terms by the denominator


-16x*2x+1*2x+2*2x+1=0

Wy multiply elements

-32x^2+2x+4x+1=0

We add all the numbers together, and all the variables

-32x^2+6x+1=0

a = -32; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·(-32)·1
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{41}}{2*-32}=\frac{-6-2\sqrt{41}}{-64}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{41}}{2*-32}=\frac{-6+2\sqrt{41}}{-64}
$