1/2x+271/2+3/4x=90

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Solution for 1/2x+271/2+3/4x=90 equation:



1/2x+271/2+3/4x=90
We move all terms to the left:
1/2x+271/2+3/4x-(90)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
determiningTheFunctionDomain 1/2x+3/4x-90+271/2=0
We calculate fractions
4x/32x^2+24x/32x^2+1084x/32x^2-90=0
We multiply all the terms by the denominator
4x+24x+1084x-90*32x^2=0
We add all the numbers together, and all the variables
1112x-90*32x^2=0
Wy multiply elements
-2880x^2+1112x=0
a = -2880; b = 1112; c = 0;
Δ = b2-4ac
Δ = 11122-4·(-2880)·0
Δ = 1236544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1236544}=1112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1112)-1112}{2*-2880}=\frac{-2224}{-5760} =139/360 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1112)+1112}{2*-2880}=\frac{0}{-5760} =0 $

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