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1/2x+2/5=2/5x
We move all terms to the left:
1/2x+2/5-(2/5x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2x-(+2/5x)+2/5=0
We get rid of parentheses
1/2x-2/5x+2/5=0
We calculate fractions
125x/250x^2+(-4x)/250x^2+4x/250x^2=0
We multiply all the terms by the denominator
125x+(-4x)+4x=0
We add all the numbers together, and all the variables
129x+(-4x)=0
We get rid of parentheses
129x-4x=0
We add all the numbers together, and all the variables
125x=0
x=0/125
x=0
Równanie nie ma rozwiązania
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