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1/2x+2/3x=1/4
We move all terms to the left:
1/2x+2/3x-(1/4)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/2x+2/3x-(+1/4)=0
We get rid of parentheses
1/2x+2/3x-1/4=0
We calculate fractions
(-18x^2)/96x^2+48x/96x^2+64x/96x^2=0
We multiply all the terms by the denominator
(-18x^2)+48x+64x=0
We add all the numbers together, and all the variables
(-18x^2)+112x=0
We get rid of parentheses
-18x^2+112x=0
a = -18; b = 112; c = 0;
Δ = b2-4ac
Δ = 1122-4·(-18)·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-112}{2*-18}=\frac{-224}{-36} =6+2/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+112}{2*-18}=\frac{0}{-36} =0 $
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