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1/2x+2/3=3/4x-2
We move all terms to the left:
1/2x+2/3-(3/4x-2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x-2)!=0We get rid of parentheses
x∈R
1/2x-3/4x+2+2/3=0
We calculate fractions
64x^2/72x^2+36x/72x^2+(-54x)/72x^2+2=0
We multiply all the terms by the denominator
64x^2+36x+(-54x)+2*72x^2=0
Wy multiply elements
64x^2+144x^2+36x+(-54x)=0
We get rid of parentheses
64x^2+144x^2+36x-54x=0
We add all the numbers together, and all the variables
208x^2-18x=0
a = 208; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·208·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*208}=\frac{0}{416} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*208}=\frac{36}{416} =9/104 $
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