1/2x+1=1/8x+8

Solution for 1/2x+1=1/8x+8 equation:

1/2x+1=1/8x+8

We move all terms to the left:

1/2x+1-(1/8x+8)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 8x+8)!=0

x∈R


We get rid of parentheses

1/2x-1/8x-8+1=0

We calculate fractions


8x/16x^2+(-2x)/16x^2-8+1=0

We add all the numbers together, and all the variables

8x/16x^2+(-2x)/16x^2-7=0

We multiply all the terms by the denominator


8x+(-2x)-7*16x^2=0

Wy multiply elements

-112x^2+8x+(-2x)=0

We get rid of parentheses

-112x^2+8x-2x=0

We add all the numbers together, and all the variables

-112x^2+6x=0

a = -112; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-112)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-112}=\frac{-12}{-224}
=3/56
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-112}=\frac{0}{-224}
=0
$