1/2x+13x=10

Solution for 1/2x+13x=10 equation:

1/2x+13x=10

We move all terms to the left:

1/2x+13x-(10)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

13x+1/2x-10=0

We multiply all the terms by the denominator


13x*2x-10*2x+1=0

Wy multiply elements

26x^2-20x+1=0

a = 26; b = -20; c = +1;
Δ = b2-4ac
Δ = -202-4·26·1
Δ = 296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{296}=\sqrt{4*74}=\sqrt{4}*\sqrt{74}=2\sqrt{74}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{74}}{2*26}=\frac{20-2\sqrt{74}}{52}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{74}}{2*26}=\frac{20+2\sqrt{74}}{52}
$