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1/2x+10=1/x+54
We move all terms to the left:
1/2x+10-(1/x+54)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x+54)!=0We get rid of parentheses
x∈R
1/2x-1/x-54+10=0
We calculate fractions
x/2x^2+(-2x)/2x^2-54+10=0
We add all the numbers together, and all the variables
x/2x^2+(-2x)/2x^2-44=0
We multiply all the terms by the denominator
x+(-2x)-44*2x^2=0
Wy multiply elements
-88x^2+x+(-2x)=0
We get rid of parentheses
-88x^2+x-2x=0
We add all the numbers together, and all the variables
-88x^2-1x=0
a = -88; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-88)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-88}=\frac{0}{-176} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-88}=\frac{2}{-176} =-1/88 $
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