1/2x+1/6(2-x)=-1/3(2-x)+2

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Solution for 1/2x+1/6(2-x)=-1/3(2-x)+2 equation: 


x in (-oo:+oo)

(1/6)*(2-x)+(1/2)*x = (-1/3)*(2-x)+2 // - (-1/3)*(2-x)+2

(1/6)*(2-x)-((-1/3)*(2-x))+(1/2)*x-2 = 0

(1/6)*(2-x)+(1/3)*(2-x)+(1/2)*x-2 = 0

1/6*(2-x)+1/3*(2-x)+x/2-2 = 0

(1/6*2*(2-x))/2+(1/3*2*(2-x))/2+x/2+(-2*2)/2 = 0

1/6*2*(2-x)+1/3*2*(2-x)+x-2*2 = 0

x-x-4+2 = 0

2-4 = 0

-2 = 0

-2/2 = 0

-2/2 = 0 // * 2

-2 = 0

x belongs to the empty set

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