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1/2x+1/4x=24
We move all terms to the left:
1/2x+1/4x-(24)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x!=0We calculate fractions
x!=0/4
x!=0
x∈R
4x/8x^2+2x/8x^2-24=0
We multiply all the terms by the denominator
4x+2x-24*8x^2=0
We add all the numbers together, and all the variables
6x-24*8x^2=0
Wy multiply elements
-192x^2+6x=0
a = -192; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-192)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-192}=\frac{-12}{-384} =1/32 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-192}=\frac{0}{-384} =0 $
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