1/2x+1/2x=20x=

Solution for 1/2x+1/2x=20x= equation:

1/2x+1/2x=20x=

We move all terms to the left:

1/2x+1/2x-(20x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

-20x+1/2x+1/2x=0

We multiply all the terms by the denominator


-20x*2x+1+1=0

We add all the numbers together, and all the variables

-20x*2x+2=0

Wy multiply elements

-40x^2+2=0

a = -40; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-40)·2
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{5}}{2*-40}=\frac{0-8\sqrt{5}}{-80}
=-\frac{8\sqrt{5}}{-80}
=-\frac{\sqrt{5}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{5}}{2*-40}=\frac{0+8\sqrt{5}}{-80}
=\frac{8\sqrt{5}}{-80}
=\frac{\sqrt{5}}{-10}
$