If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(1/2)*x+(1/2)*x = 1*x+1 // - 1*x+1
(1/2)*x+(1/2)*x-(1*x)-1 = 0
(1/2)*x+(1/2)*x-x-1 = 0
-1 = 0
x belongs to the empty set
x belongs to the empty set
| 4x-(4-3x)=8x-1 | | 8-2(n-3)=30 | | 63-4x=19 | | 8x-5c+7b=5x-2c+10b | | 5(n+3)=3(1)-2n | | 3i/4+2i | | 3x^2-72n+432=0 | | 20y^3+31y^2+12y=0 | | 8[3x+6]=9[2x-4] | | 8=5n+2 | | -11+3(x+5)=7 | | -2(3x-2)=48 | | 7-2x+6=11 | | 5/2n+3=18 | | 4p+5=4p+7 | | 10y=x | | 5x^2-10xy-3x+6y=0 | | 5/12=h/28 | | 3(x-6)=4x(x+10) | | 3x?4=2x+1 | | 4/5n-14=6 | | (-2x^5)(-3x^4)(5x^3)= | | 4(3x-2)+12x=40 | | 68+n= | | 2.5=2x/(1-2x) | | 2x+8+5=28 | | f+6/25=-21 | | C+3/3=2c | | 42+11=42+8 | | 2(3x-2)=48 | | b-x=dforx | | h(t)=-16t+64t |