1/2x+(8-x)+x+(1/2x+(8-x))=12

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Solution for 1/2x+(8-x)+x+(1/2x+(8-x))=12 equation: 



1/2x+(8-x)+x+(1/2x+(8-x))=12

We move all terms to the left:

1/2x+(8-x)+x+(1/2x+(8-x))-(12)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 2x+(8-x))!=0

x∈R



We add all the numbers together, and all the variables

1/2x+(-1x+8)+x+(1/2x+(-1x+8))-12=0

We add all the numbers together, and all the variables

x+1/2x+(-1x+8)+(1/2x+(-1x+8))-12=0

We get rid of parentheses

x+1/2x-1x+(1/2x+(-1x+8))+8-12=0

We calculate fractions


x-1x+x/(4x^2-1x)+((1*2x)/(4x^2-1x)+8-12=0

We add all the numbers together, and all the variables

x-1x+x/(4x^2-1x)+((+1*2x)/(4x^2-1x)+8-12=0

We add all the numbers together, and all the variables

x/(4x^2-1x)+((+1*2x)/(4x^2-1x)+8-12=0

We calculate fractions

We do not support expression: x^3

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