1/2x^2+(4x-5)=-1

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Solution for 1/2x^2+(4x-5)=-1 equation: 



1/2x^2+(4x-5)=-1

We move all terms to the left:

1/2x^2+(4x-5)-(-1)=0



Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

1/2x^2+(4x-5)+1=0

We get rid of parentheses

1/2x^2+4x-5+1=0

We multiply all the terms by the denominator


4x*2x^2-5*2x^2+1*2x^2+1=0

Wy multiply elements

8x^3-10x^2+2x^2+1=0

We do not support expression: x^3

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