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1/2u-3=2-3/4u
We move all terms to the left:
1/2u-3-(2-3/4u)=0
Domain of the equation: 2u!=0
u!=0/2
u!=0
u∈R
Domain of the equation: 4u)!=0We add all the numbers together, and all the variables
u!=0/1
u!=0
u∈R
1/2u-(-3/4u+2)-3=0
We get rid of parentheses
1/2u+3/4u-2-3=0
We calculate fractions
4u/8u^2+6u/8u^2-2-3=0
We add all the numbers together, and all the variables
4u/8u^2+6u/8u^2-5=0
We multiply all the terms by the denominator
4u+6u-5*8u^2=0
We add all the numbers together, and all the variables
10u-5*8u^2=0
Wy multiply elements
-40u^2+10u=0
a = -40; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-40)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-40}=\frac{-20}{-80} =1/4 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-40}=\frac{0}{-80} =0 $
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