1/2n=1/n

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Solution for 1/2n=1/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

(1/2)*n = 1/n // - 1/n

(1/2)*n-(1/n) = 0

(1/2)*n-n^-1 = 0

1/2*n^1-1*n^-1 = 0

(1/2*n^2-1*n^0)/(n^1) = 0 // * n^2

n^1*(1/2*n^2-1*n^0) = 0

n^1

(1/2)*n^2-1 = 0

(1/2)*n^2-1 = 0

DELTA = 0^2-(-1*4*(1/2))

DELTA = 2

DELTA > 0

n = (2^(1/2)+0)/(2*(1/2)) or n = (0-2^(1/2))/(2*(1/2))

n = 2^(1/2) or n = -2^(1/2)

n in { -2^(1/2), 2^(1/2)} 

n in { -2^(1/2), 2^(1/2) }

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