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1/2n+15=5+3n
We move all terms to the left:
1/2n+15-(5+3n)=0
Domain of the equation: 2n!=0We add all the numbers together, and all the variables
n!=0/2
n!=0
n∈R
1/2n-(3n+5)+15=0
We get rid of parentheses
1/2n-3n-5+15=0
We multiply all the terms by the denominator
-3n*2n-5*2n+15*2n+1=0
Wy multiply elements
-6n^2-10n+30n+1=0
We add all the numbers together, and all the variables
-6n^2+20n+1=0
a = -6; b = 20; c = +1;
Δ = b2-4ac
Δ = 202-4·(-6)·1
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-2\sqrt{106}}{2*-6}=\frac{-20-2\sqrt{106}}{-12} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+2\sqrt{106}}{2*-6}=\frac{-20+2\sqrt{106}}{-12} $
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