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1/2m=5/4m+2
We move all terms to the left:
1/2m-(5/4m+2)=0
Domain of the equation: 2m!=0
m!=0/2
m!=0
m∈R
Domain of the equation: 4m+2)!=0We get rid of parentheses
m∈R
1/2m-5/4m-2=0
We calculate fractions
4m/8m^2+(-10m)/8m^2-2=0
We multiply all the terms by the denominator
4m+(-10m)-2*8m^2=0
Wy multiply elements
-16m^2+4m+(-10m)=0
We get rid of parentheses
-16m^2+4m-10m=0
We add all the numbers together, and all the variables
-16m^2-6m=0
a = -16; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-16)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-16}=\frac{0}{-32} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-16}=\frac{12}{-32} =-3/8 $
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