1/2m+1/4m=10

Solution for 1/2m+1/4m=10 equation:

1/2m+1/4m=10

We move all terms to the left:

1/2m+1/4m-(10)=0


Domain of the equation: 2m!=0

m!=0/2

m!=0

m∈R



Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R


We calculate fractions


4m/8m^2+2m/8m^2-10=0

We multiply all the terms by the denominator


4m+2m-10*8m^2=0

We add all the numbers together, and all the variables

6m-10*8m^2=0

Wy multiply elements

-80m^2+6m=0

a = -80; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-80)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-80}=\frac{-12}{-160}
=3/40
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-80}=\frac{0}{-160}
=0
$