1/2k-(k+1/5)=1/10(k+1)

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Solution for 1/2k-(k+1/5)=1/10(k+1) equation: 


k in (-oo:+oo)

(1/2)*k-k-(1/5) = (1/10)*(k+1) // - (1/10)*(k+1)

(1/2)*k-((1/10)*(k+1))-k-(1/5) = 0

(-1/10)*(k+1)+(1/2)*k-k-1/5 = 0

k/2-1/10*(k+1)-k-1/5 = 0

(-1/10*2*5*(k+1))/(2*5)+(5*k)/(2*5)+(2*5*(-k))/(2*5)+(-1*2)/(2*5) = 0

5*k-1/10*2*5*(k+1)+2*5*(-k)-1*2 = 0

4*k-10*k-2-1 = 0

-6*k-2-1 = 0

-6*k-3 = 0

(-6*k-3)/(2*5) = 0

(-6*k-3)/(2*5) = 0 // * 2*5

-6*k-3 = 0

-6*k-3 = 0 // + 3

-6*k = 3 // : -6

k = 3/(-6)

k = -1/2

k = -1/2

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