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1/2k+4=2(k+2)
We move all terms to the left:
1/2k+4-(2(k+2))=0
Domain of the equation: 2k!=0We multiply all the terms by the denominator
k!=0/2
k!=0
k∈R
-((2(k+2)))*2k+4*2k+1=0
Wy multiply elements
-((2(k+2)))*2k+8k+1=0
We add all the numbers together, and all the variables
8k-((2(k+2)))*2k+1=0
We move all terms containing k to the left, all other terms to the right
8k-((2(k+2)))*2k=-1
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