1/2j+-3=1/3j+-4+j

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Solution for 1/2j+-3=1/3j+-4+j equation:



1/2j+-3=1/3j+-4+j
We move all terms to the left:
1/2j+-3-(1/3j+-4+j)=0
Domain of the equation: 2j!=0
j!=0/2
j!=0
j∈R
Domain of the equation: 3j+-4+j)!=0
We move all terms containing j to the left, all other terms to the right
3j+j)+!=4
j∈R
We add all the numbers together, and all the variables
1/2j-(j+1/3j-4)-3+=0
We add all the numbers together, and all the variables
1/2j-(j+1/3j-4)=0
We get rid of parentheses
1/2j-j-1/3j+4=0
We calculate fractions
-j+3j/6j^2+(-2j)/6j^2+4=0
We add all the numbers together, and all the variables
-1j+3j/6j^2+(-2j)/6j^2+4=0
We multiply all the terms by the denominator
-1j*6j^2+3j+(-2j)+4*6j^2=0
We add all the numbers together, and all the variables
3j-1j*6j^2+(-2j)+4*6j^2=0
Wy multiply elements
-6j^3+24j^2+3j+(-2j)=0
We get rid of parentheses
-6j^3+24j^2+3j-2j=0
We do not support ejpression: j^3

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