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1/2h+1/3(h-6)=h+2
We move all terms to the left:
1/2h+1/3(h-6)-(h+2)=0
Domain of the equation: 2h!=0
h!=0/2
h!=0
h∈R
Domain of the equation: 3(h-6)!=0We get rid of parentheses
h∈R
1/2h+1/3(h-6)-h-2=0
We calculate fractions
-h+(3hh/(6h^2h+2h/(6h^2h-2=0
We can not solve this equation
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