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1/2g=8g=
We move all terms to the left:
1/2g-(8g)=0
Domain of the equation: 2g!=0We add all the numbers together, and all the variables
g!=0/2
g!=0
g∈R
-8g+1/2g=0
We multiply all the terms by the denominator
-8g*2g+1=0
Wy multiply elements
-16g^2+1=0
a = -16; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-16)·1
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*-16}=\frac{-8}{-32} =1/4 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*-16}=\frac{8}{-32} =-1/4 $
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