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1/2g-1.5=0.5g-1.5
We move all terms to the left:
1/2g-1.5-(0.5g-1.5)=0
Domain of the equation: 2g!=0We get rid of parentheses
g!=0/2
g!=0
g∈R
1/2g-0.5g+1.5-1.5=0
We multiply all the terms by the denominator
-(0.5g)*2g+(1.5)*2g-(1.5)*2g+1=0
We add all the numbers together, and all the variables
-(+0.5g)*2g+(1.5)*2g-(1.5)*2g+1=0
We multiply parentheses
-0g^2+3g-3g+1=0
We add all the numbers together, and all the variables
-1g^2+1=0
a = -1; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-1)·1
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2}{2*-1}=\frac{-2}{-2} =1 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2}{2*-1}=\frac{2}{-2} =-1 $
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