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1/2e+3=2/3e-1
We move all terms to the left:
1/2e+3-(2/3e-1)=0
Domain of the equation: 2e!=0
e!=0/2
e!=0
e∈R
Domain of the equation: 3e-1)!=0We get rid of parentheses
e∈R
1/2e-2/3e+1+3=0
We calculate fractions
3e/6e^2+(-4e)/6e^2+1+3=0
We add all the numbers together, and all the variables
3e/6e^2+(-4e)/6e^2+4=0
We multiply all the terms by the denominator
3e+(-4e)+4*6e^2=0
Wy multiply elements
24e^2+3e+(-4e)=0
We get rid of parentheses
24e^2+3e-4e=0
We add all the numbers together, and all the variables
24e^2-1e=0
a = 24; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·24·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*24}=\frac{0}{48} =0 $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*24}=\frac{2}{48} =1/24 $
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