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1/2d-3=2/3d
We move all terms to the left:
1/2d-3-(2/3d)=0
Domain of the equation: 2d!=0
d!=0/2
d!=0
d∈R
Domain of the equation: 3d)!=0We add all the numbers together, and all the variables
d!=0/1
d!=0
d∈R
1/2d-(+2/3d)-3=0
We get rid of parentheses
1/2d-2/3d-3=0
We calculate fractions
3d/6d^2+(-4d)/6d^2-3=0
We multiply all the terms by the denominator
3d+(-4d)-3*6d^2=0
Wy multiply elements
-18d^2+3d+(-4d)=0
We get rid of parentheses
-18d^2+3d-4d=0
We add all the numbers together, and all the variables
-18d^2-1d=0
a = -18; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-18)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-18}=\frac{0}{-36} =0 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-18}=\frac{2}{-36} =-1/18 $
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