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1/2b-2/3=5/6b
We move all terms to the left:
1/2b-2/3-(5/6b)=0
Domain of the equation: 2b!=0
b!=0/2
b!=0
b∈R
Domain of the equation: 6b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
1/2b-(+5/6b)-2/3=0
We get rid of parentheses
1/2b-5/6b-2/3=0
We calculate fractions
(-144b^2)/108b^2+54b/108b^2+(-90b)/108b^2=0
We multiply all the terms by the denominator
(-144b^2)+54b+(-90b)=0
We get rid of parentheses
-144b^2+54b-90b=0
We add all the numbers together, and all the variables
-144b^2-36b=0
a = -144; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·(-144)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*-144}=\frac{0}{-288} =0 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*-144}=\frac{72}{-288} =-1/4 $
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