1/2b+4=1/4b+88

Solution for 1/2b+4=1/4b+88 equation:

1/2b+4=1/4b+88

We move all terms to the left:

1/2b+4-(1/4b+88)=0


Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



Domain of the equation: 4b+88)!=0

b∈R


We get rid of parentheses

1/2b-1/4b-88+4=0

We calculate fractions


4b/8b^2+(-2b)/8b^2-88+4=0

We add all the numbers together, and all the variables

4b/8b^2+(-2b)/8b^2-84=0

We multiply all the terms by the denominator


4b+(-2b)-84*8b^2=0

Wy multiply elements

-672b^2+4b+(-2b)=0

We get rid of parentheses

-672b^2+4b-2b=0

We add all the numbers together, and all the variables

-672b^2+2b=0

a = -672; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-672)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-672}=\frac{-4}{-1344}
=1/336
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-672}=\frac{0}{-1344}
=0
$