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1/2b+1/4b=3/4
We move all terms to the left:
1/2b+1/4b-(3/4)=0
Domain of the equation: 2b!=0
b!=0/2
b!=0
b∈R
Domain of the equation: 4b!=0We add all the numbers together, and all the variables
b!=0/4
b!=0
b∈R
1/2b+1/4b-(+3/4)=0
We get rid of parentheses
1/2b+1/4b-3/4=0
We calculate fractions
64b/128b^2+2b/128b^2+(-6b)/128b^2=0
We multiply all the terms by the denominator
64b+2b+(-6b)=0
We add all the numbers together, and all the variables
66b+(-6b)=0
We get rid of parentheses
66b-6b=0
We add all the numbers together, and all the variables
60b=0
b=0/60
b=0
Równanie nie ma rozwiązania
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