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1/2a-2=1/3a-1
We move all terms to the left:
1/2a-2-(1/3a-1)=0
Domain of the equation: 2a!=0
a!=0/2
a!=0
a∈R
Domain of the equation: 3a-1)!=0We get rid of parentheses
a∈R
1/2a-1/3a+1-2=0
We calculate fractions
3a/6a^2+(-2a)/6a^2+1-2=0
We add all the numbers together, and all the variables
3a/6a^2+(-2a)/6a^2-1=0
We multiply all the terms by the denominator
3a+(-2a)-1*6a^2=0
Wy multiply elements
-6a^2+3a+(-2a)=0
We get rid of parentheses
-6a^2+3a-2a=0
We add all the numbers together, and all the variables
-6a^2+a=0
a = -6; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-6)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-6}=\frac{-2}{-12} =1/6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-6}=\frac{0}{-12} =0 $
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