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1/2a-12=5/4a+6
We move all terms to the left:
1/2a-12-(5/4a+6)=0
Domain of the equation: 2a!=0
a!=0/2
a!=0
a∈R
Domain of the equation: 4a+6)!=0We get rid of parentheses
a∈R
1/2a-5/4a-6-12=0
We calculate fractions
4a/8a^2+(-10a)/8a^2-6-12=0
We add all the numbers together, and all the variables
4a/8a^2+(-10a)/8a^2-18=0
We multiply all the terms by the denominator
4a+(-10a)-18*8a^2=0
Wy multiply elements
-144a^2+4a+(-10a)=0
We get rid of parentheses
-144a^2+4a-10a=0
We add all the numbers together, and all the variables
-144a^2-6a=0
a = -144; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-144)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-144}=\frac{0}{-288} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-144}=\frac{12}{-288} =-1/24 $
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