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1/2a+3a=20
We move all terms to the left:
1/2a+3a-(20)=0
Domain of the equation: 2a!=0We add all the numbers together, and all the variables
a!=0/2
a!=0
a∈R
3a+1/2a-20=0
We multiply all the terms by the denominator
3a*2a-20*2a+1=0
Wy multiply elements
6a^2-40a+1=0
a = 6; b = -40; c = +1;
Δ = b2-4ac
Δ = -402-4·6·1
Δ = 1576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1576}=\sqrt{4*394}=\sqrt{4}*\sqrt{394}=2\sqrt{394}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-2\sqrt{394}}{2*6}=\frac{40-2\sqrt{394}}{12} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+2\sqrt{394}}{2*6}=\frac{40+2\sqrt{394}}{12} $
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