1/20-7/4u=11/5u

Solution for 1/20-7/4u=11/5u equation:

1/20-7/4u=11/5u

We move all terms to the left:

1/20-7/4u-(11/5u)=0


Domain of the equation: 4u!=0

u!=0/4

u!=0

u∈R



Domain of the equation: 5u)!=0

u!=0/1

u!=0

u∈R


We add all the numbers together, and all the variables

-7/4u-(+11/5u)+1/20=0

We get rid of parentheses

-7/4u-11/5u+1/20=0

We calculate fractions


100u^2/800u^2+(-1400u)/800u^2+(-1760u)/800u^2=0

We multiply all the terms by the denominator


100u^2+(-1400u)+(-1760u)=0

We get rid of parentheses

100u^2-1400u-1760u=0

We add all the numbers together, and all the variables

100u^2-3160u=0

a = 100; b = -3160; c = 0;
Δ = b2-4ac
Δ = -31602-4·100·0
Δ = 9985600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9985600}=3160$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3160)-3160}{2*100}=\frac{0}{200}
=0
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3160)+3160}{2*100}=\frac{6320}{200}
=31+3/5
$