1/2-7/2y=5/y

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Solution for 1/2-7/2y=5/y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/2-((7/2)*y) = 5/y // - 5/y

1/2-((7/2)*y)-(5/y) = 0

(-7/2)*y-5*y^-1+1/2 = 0

1/2*y^0-7/2*y^1-5*y^-1 = 0

(1/2*y^1-7/2*y^2-5*y^0)/(y^1) = 0 // * y^2

y^1*(1/2*y^1-7/2*y^2-5*y^0) = 0

y^1

(-7/2)*y^2+(1/2)*y-5 = 0

(-7/2)*y^2+(1/2)*y-5 = 0

DELTA = (1/2)^2-(-5*4*(-7/2))

DELTA = -279/4

DELTA < 0

y in { } 

y belongs to the empty set

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