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1/2+2/x=13/3x
We move all terms to the left:
1/2+2/x-(13/3x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/x-(+13/3x)+1/2=0
We get rid of parentheses
2/x-13/3x+1/2=0
We calculate fractions
9x^2/12x^2+24x/12x^2+(-52x)/12x^2=0
We multiply all the terms by the denominator
9x^2+24x+(-52x)=0
We get rid of parentheses
9x^2+24x-52x=0
We add all the numbers together, and all the variables
9x^2-28x=0
a = 9; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·9·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*9}=\frac{0}{18} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*9}=\frac{56}{18} =3+1/9 $
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