1/2(y-3)+(y-3)+y=68

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Solution for 1/2(y-3)+(y-3)+y=68 equation: 



1/2(y-3)+(y-3)+y=68

We move all terms to the left:

1/2(y-3)+(y-3)+y-(68)=0



Domain of the equation: 2(y-3)!=0

y∈R



We add all the numbers together, and all the variables

y+1/2(y-3)+(y-3)-68=0

We get rid of parentheses

y+1/2(y-3)+y-3-68=0

We multiply all the terms by the denominator


y*2(y-3)+y*2(y-3)-3*2(y-3)-68*2(y-3)+1=0

Wy multiply elements

2y^2(y+2y^2(y-6y(y-136y(y+1=0

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