1/2(x-8)=(3/2x)+7

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Solution for 1/2(x-8)=(3/2x)+7 equation: 



1/2(x-8)=(3/2x)+7

We move all terms to the left:

1/2(x-8)-((3/2x)+7)=0



Domain of the equation: 2(x-8)!=0

x∈R





Domain of the equation: 2x)+7)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/2(x-8)-((+3/2x)+7)=0

We calculate fractions


2x/(-32x^2+2x)+(-((+3*2(x-8))/(-32x^2+2x)=0



We calculate terms in parentheses: +(-((+3*2(x-8))/(-32x^2+2x), so:

-((+3*2(x-8))/(-32x^2+2x

We multiply all the terms by the denominator


-((+3*2(x-8))



We calculate terms in parentheses: -((+3*2(x-8)), so:

(+3*2(x-8)



We calculate terms in parentheses: +(+3*2(x-8), so:

+3*2(x-8

determiningTheFunctionDomain
3*2(x-8

Wy multiply elements

6x(x

Back to the equation:

+(6x(x)



Back to the equation:

-((6xx)



Back to the equation:

+(-(6xx)



We multiply all the terms by the denominator


((-6xx)*(-32x^2+2x)+2x=0

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