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1/2(x-5)+2/3x=x
We move all terms to the left:
1/2(x-5)+2/3x-(x)=0
Domain of the equation: 2(x-5)!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-1x+1/2(x-5)+2/3x=0
We calculate fractions
-1x+3x/(6x^2-30x)+(4xx/(6x^2-30x)=0
We calculate terms in parentheses: +(4xx/(6x^2-30x), so:We multiply all the terms by the denominator
4xx/(6x^2-30x
We multiply all the terms by the denominator
4xx
Back to the equation:
+(4xx)
-1x*(6x^2-30x)+3x+4xx*(6x^2-30x)=0
We add all the numbers together, and all the variables
3x-1x*(6x^2-30x)+4xx*(6x^2-30x)=0
We multiply parentheses
-6x^3+30x^2+24x^3-120x^2+3x=0
We do not support expression: x^3
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