1/2(x-4)=3-2/3(6-x)

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Solution for 1/2(x-4)=3-2/3(6-x) equation: 



1/2(x-4)=3-2/3(6-x)

We move all terms to the left:

1/2(x-4)-(3-2/3(6-x))=0



Domain of the equation: 2(x-4)!=0

x∈R





Domain of the equation: 3(6-x))!=0

x∈R



We add all the numbers together, and all the variables

1/2(x-4)-(3-2/3(-1x+6))=0

We calculate fractions


(3x(-)/(2(x-4)*3(-1x+6)))+(-(-4xx)/(2(x-4)*3(-1x+6)))=0



We calculate terms in parentheses: +(3x(-)/(2(x-4)*3(-1x+6))), so:

3x(-)/(2(x-4)*3(-1x+6))

We add all the numbers together, and all the variables

3x0/(2(x-4)*3(-1x+6))

We multiply all the terms by the denominator


3x0

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-(-4xx)/(2(x-4)*3(-1x+6))), so:

-(-4xx)/(2(x-4)*3(-1x+6))

We multiply all the terms by the denominator


-(-4xx)

We get rid of parentheses

4xx

Back to the equation:

+(4xx)

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