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1/2(x-4)=1/5(x-1)
We move all terms to the left:
1/2(x-4)-(1/5(x-1))=0
Domain of the equation: 2(x-4)!=0
x∈R
Domain of the equation: 5(x-1))!=0We calculate fractions
x∈R
(5xx/(2(x-4)*5(x-1)))+(-2xx/(2(x-4)*5(x-1)))=0
We calculate terms in parentheses: +(5xx/(2(x-4)*5(x-1))), so:
5xx/(2(x-4)*5(x-1))
We multiply all the terms by the denominator
5xx
Back to the equation:
+(5xx)
We calculate terms in parentheses: +(-2xx/(2(x-4)*5(x-1))), so:We get rid of parentheses
-2xx/(2(x-4)*5(x-1))
We multiply all the terms by the denominator
-2xx
Back to the equation:
+(-2xx)
5xx-2xx=0
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