1/2(x-10)=47+7x

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Solution for 1/2(x-10)=47+7x equation: 



1/2(x-10)=47+7x

We move all terms to the left:

1/2(x-10)-(47+7x)=0



Domain of the equation: 2(x-10)!=0

x∈R



We add all the numbers together, and all the variables

1/2(x-10)-(7x+47)=0

We get rid of parentheses

1/2(x-10)-7x-47=0

We multiply all the terms by the denominator


-7x*2(x-10)-47*2(x-10)+1=0

Wy multiply elements

-14x^2(x-94x(x+1=0

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